GrowMock

Mathematics

Circle and Disk

Length and Area

R is the radius of the circle. Circumference C = 2πR, area of the disk S = πR².

Part Formula
Arc length (α in degrees) l = πRα / 180
Sector area S = πR²α / 360
Segment area sector area minus triangle area

Angles

  • A central angle is equal to the arc it subtends.
  • Inscribed angle = half of the arc.
  • Inscribed angles subtending the same arc are equal; an inscribed angle subtending a diameter is 90°.
  • The angle between a tangent and a chord is equal to half of the arc.

Chords, Tangent, Secant

  • Intersecting chords: AE · EB = CE · ED.
  • A tangent is perpendicular to the radius at the point of tangency.
  • Two tangent segments drawn from one point are equal.
  • Tangent and secant: PT² = PA · PB (PT is the tangent segment, PA is the external part of the secant, PB is the whole secant).
  • For intersecting chords, the product is the product of the parts, not of the whole chord.
  • An inscribed angle is half the arc, a central angle equals the arc itself: do not equate the inscribed angle to the arc.

Relation to Triangles and Quadrilaterals

  • Radius of the inscribed circle: r = S / p (p is the semiperimeter).
  • Circumscribed circle: R = abc / 4S. In a right triangle R = c/2, r = (a + b − c)/2 (c is the hypotenuse).
  • In an inscribed quadrilateral, the sum of opposite angles is 180°.
  • In a circumscribed quadrilateral, the sums of opposite sides are equal: a + c = b + d.
  1. Mark the central and inscribed angles and the arcs on the diagram
  2. Choose the suitable theorem: chords, tangent, or the perpendicularity of radius and tangent
  3. Substitute into the formula and find the unknown
  4. Check the units (degrees or radians)

Examples

  • R = 6, central angle 60°. Sector area 36π · 60 / 360 = 6π.
  • Chords intersect, AE = 4, EB = 6, CE = 3: ED = 24 / 3 = 8.
  • In a right triangle with legs 6 and 8, the hypotenuse is 10, r = (6 + 8 − 10)/2 = 2.