GrowMock

Mathematics

Vectors

Basic concepts

A vector is a directed line segment. Its coordinates are written as a = (x; y).

  • Vector length |a|: length: √(x² + y²). In space, |a| = √(x² + y² + z²).
  • The vector from A(x₁; y₁) to B(x₂; y₂): AB = (x₂ − x₁; y₂ − y₁). That is, the end point minus the starting point.
  • Midpoint of a segment: M((x₁ + x₂)/2; (y₁ + y₂)/2).

Operations

Operation In coordinates
Sum (x₁ + x₂; y₁ + y₂)
Difference (x₁ − x₂; y₁ − y₂)
Multiplication by a number k · a = (kx; ky)

Dot product

  • a · b = x₁x₂ + y₁y₂
  • a · b = |a| · |b| · cos φ, hence cos φ = (a · b) / (|a| · |b|).
  • if a · b = 0, the vectors are perpendicular (for nonzero vectors).
  • Collinear (parallel) vectors: x₁ / x₂ = y₁ / y₂, that is, x₁y₂ = x₂y₁.
  • a · a = |a|².
  1. Find the vector's coordinates (end minus start)
  2. Choose the required quantity: length, dot product, angle
  3. Substitute the values into the formula
  4. Use the sign of cos φ to check whether the angle is acute or obtuse

Examples

  • If a = (−6; 8), then |a| = √(36 + 64) = 10.
  • a = (2; −1), b = (3; 4): a · b = 6 − 4 = 2.
  • a = (2; k), b = (3; −6) are perpendicular: 6 − 6k = 0, k = 1. If they are collinear, 2 / 3 = k / (−6), k = −4.
  • a = (1; √3), b = (−2; 0): a · b = −2, |a| = 2, |b| = 2, cos φ = −1/2, φ = 120°.

Mistakes

  • if cos φ is negative, the angle is obtuse; do not replace it with 60°.
  • The condition for perpendicularity is that the dot product equals zero; the condition for collinearity is proportionality.